**1. If the surface warms, this causes increased evaporation and water vapor which:**

a. increases clouds, which reflects more sunlight to space [increased albedo], which decreases solar radiation at the surface and causes cooling to restore balance.

b. increased water vapor increases the heat capacity of the atmosphere [Cp], which decreases the natural adiabatic lapse rate = dT/h = -g/Cp [g = gravity, Cp=heat capacity, h=height, dT change in temperature]. A decrease of the lapse rate causes cooling of the surface by shifting and tilting to the left the lapse rate temperature profile shown on the figure below:

This shift and tilt of the lapse rate temperature profile to the left [cooling] decreases the mean radiating height of the atmosphere. Since the atmosphere is warmer at this decreased mean radiating height, more infrared radiation will be emitted by greenhouse gases to space, thus cooling the planet to restore balance. Note, there is no term for radiative forcing from greenhouse gases in the lapse rate formula and radiative forcing from greenhouse gases does not affect the lapse rate. Therefore, man-made CO2 has a trivial influence on climate.

**The opposite is true if the surface cools:**

**2. If the surface cools, this causes decreased evaporation and water vapor which:**

a. decreases clouds, which reflects less sunlight to space [decreased albedo], which increases solar radiation at the surface and causes warming to restore balance.

b. decreased water vapor decreases the heat capacity of the atmosphere [Cp], which increases the natural adiabatic lapse rate = dT/h = -g/Cp [g = gravity, Cp=heat capacity, h=height, dT change in temperature]. An increase of the lapse rate causes warming of the surface by shifting and tilting to the right the lapse rate temperature profile shown on the figure below:

This shift of the lapse rate temperature profile to the right [warming] increases the mean radiating height of the atmosphere. Since the atmosphere is colder at this increased mean radiating height, less infrared radiation will be emitted by greenhouse gases to space, thus warming the planet to restore balance. Note, there is no term for radiative forcing from greenhouse gases in the lapse rate formula and radiative forcing from greenhouse gases does not affect the lapse rate. Therefore, man-made CO2 has a trivial influence on climate.

Related: Please see Willis Eschenbach's post today at WUWT demonstrating clear observational evidence that these emergent thermodynamic phenomena control temperature and the climate, not radiative forcing.

Notes:

1. The surface temperature, as well as the entire atmospheric temperature profile, is entirely explained by solar insolation plus the behavior of adiabatic gases in a gravity field, which establishes the wet and dry adiabatic lapse rates.

2. The dry adiabatic lapse rate equation: dT/h = -g/Cp [g is gravity, Cp is heat capacity of the atmosphere] does not have a term for radiative forcing and is independent of radiative forcing.

3. Addition of water vapor increases the heat capacity Cp, which causes a decrease in the lapse rate, as is observed: the dry lapse rate is much steeper than the wet. A decrease in the lapse rate causes a cooler surface.

4. The entire 33K “greenhouse effect” is entirely explainable by the average adiabatic lapse rate i.e. the observed average lapse rate = 6.5K/km * 5 km = 33K. The 255K equilibrium temperature with the Sun at the TOA + 33K due to the lapse rate sets the surface temperature at 288K or 15C.

Illustration of an electrical circuit analogy to radiative-convective equilibrium in a planetary atmosphere. Pressure and heat capacity set the resistance [opacity] to infrared transmission illustrated as the resistor Rc above. GHGs set the resistance [opacity] to infrared transmission illustrated as the resistor Rt above. As noted, "Resistance Rc corresponds to convection "shorting out" the radiative resistance Rt, allowing more current [analogous to heat in the atmosphere] to escape. If the resistance [IR opacity] of Rt increases due to adding more greenhouse gases, the resistance [IR opacity] of Rc will automatically drop to re-establish balance and thus the current through the circuit remains the same, and analogously, the temperature of the surface of the planet remains the same and self-regulates. Source |

Here's how the dry adiabatic lapse rate is derived from basic physics, and is completely independent of radiative forcing:

ReplyDeletefrom a comment on this blog by a PhD physical chemist:

Consider a vertical gas column containing a finite and constant specific energy level (U, J/kg) that is isolated from its surroundings (no input/output of energy or mass) but which is in a gravitational field. The column will in time reach equilibrium with respect to internal specific energy but the temperature will not be uniform. At static equilibrium (adiabatic equilibrium where no macro motion exists), internal specific energy (U) is composed of both thermal energy (the energy due to molecular motion) and potential energy (the energy due to

position). The latter has to exist in a gravitational field. Thus, according to the first and second law of thermodynamics, the specific internal energy (U) for any mass parcel in the air column has to be constant and can be expressed as a sum of the thermal and potential energies. This law (expressed as specific energies) can be written:

U = CpT + gh or upon differentiation dU = CpdT + gdh (1)

where “CpT” is the enthalpy (or thermal energy) per mass unit, “g” is the gravitational acceleration, “h” is the vertical height and “gh” is the potential energy per mass unit.

At static equilibrium dU = 0 and equation (1) becomes;

CpdT + gdh = 0 (2)

Thus, according to the first and second laws of thermodynamics, for any given difference in altitude (height) the increase in specific potential energy (gdh) must be offset by a corresponding decrease in thermal energy (CpdT) and a corresponding decrease in temperature. Thus in a gravitational field an atmosphere in equilibrium must have a non- isothermal decreasing temperature distribution with altitude. This is true in an isolated air column and this basic physical phenomenon exists independent of any input/output of other energy sources such as ground temperature, convection, radiation, convection, etc. And of course equation (2) can be rewritten as:

dT/dh = -g/CpT = -9.8 K/km

which is a temperature profile often observed in our atmosphere on a daily basis. This static temperature lapse rate (in this model atmosphere) is identical to the dry adiabatic lapse rate theoretically derived in Meteorology for a convective adiabatic air parcel. In both situations it is solely a function of the magnitude of the gravitational field and the heat capacity of the atmospheric gas, and nothing else. And this relationship aptly describes the bulk of the 33ÂșC so-called “Greenhouse Effect” that is the bread and butter of the Climate Science Community.

It is remarkable that this very simple derivation is totally ignored in the field of Climate Science simply because it refutes the radiation heat transfer model as the dominant cause of the GE. Hence, that community is relying on an inadequate model to blame CO2 and innocent citizens for global warming in order to generate funding and to gain attention. If this is what “science” has become today, I, as a scientist, am ashamed.

The derivation of the dry lapse rate equation above is then used to determine the 33K "greenhouse effect" as was noted in the post:

DeleteThe dry adiabatic lapse rate equation: dT/h = -g/Cp [g is gravity, Cp is heat capacity of the atmosphere] does not have a term for radiative forcing and is independent of radiative forcing.

3. Addition of water vapor increases the heat capacity Cp, which causes a decrease in the lapse rate, as is observed: the dry lapse rate is much steeper than the wet. A decrease in the lapse rate causes a cooler surface.

4. The entire 33K “greenhouse effect” is entirely explainable by the average adiabatic lapse rate i.e. the observed average lapse rate = 6.5K/km * 5 km = 33K. The 255K equilibrium temperature with the Sun at the TOA + 33K due to the lapse rate sets the surface temperature at 288K or 15C.

For conservation of energy, the mean emission height in the atmosphere must be the level at which the temperature is equal to the equilibrium temperature with the Sun = 255K

ReplyDeleteThe mean emission height h in the atmosphere is observed to be at about 5km where T = 255K. The temperature profile of the atmosphere is determined by the average lapse rate of 6.5K/km, which determines a temperature of 255K occurs at h = 5km.

In the lapse rate formula dT/dh = -g/Cp, both dT and h are dependent variables upon the independent variable -g/Cp. Therefore, the mean emission height is determined by changes in the average heat capacity of the atmosphere only, not radiative forcing from greenhouse gases.

A recent paper published in Nature Geoscience finds:

ReplyDeleteCommon 0.1 bar tropopause in thick atmospheres set by pressure-dependent infrared transparency

A minimum atmospheric temperature, or tropopause, occurs at a pressure of around 0.1 bar in the atmospheres of Earth1, Titan2, Jupiter3, Saturn4, Uranus and Neptune4, despite great differences in atmospheric composition, gravity, internal heat and sunlight.

In all of these bodies, the tropopause separates a stratosphere with a temperature profile that is controlled by the absorption of short-wave solar radiation, from a region below characterized by convection, weather and clouds5, 6. However, it is not obvious why the tropopause occurs at the specific pressure near 0.1 bar. Here we use a simple, physically based model7 to demonstrate that, at atmospheric pressures lower than 0.1 bar, transparency to thermal radiation allows short-wave heating to dominate, creating a stratosphere. At higher pressures, atmospheres become opaque to thermal radiation, causing temperatures to increase with depth and convection to ensue. A common dependence of infrared opacity on pressure, arising from the shared physics of molecular absorption, sets the 0.1 bar tropopause. We reason that a tropopause at a pressure of approximately 0.1 bar is characteristic of many thick atmospheres, including exoplanets and exomoons in our galaxy and beyond. Judicious use of this rule could help constrain the atmospheric structure, and thus the surface environments and habitability, of exoplanets."

http://www.nature.com/ngeo/journal/v7/n1/full/ngeo2020.html

http://www.nature.com/ngeo/journal/v7/n1/carousel/ngeo2020-f1.jpg

Therefore, to determine surface temperature of any planet, start from the height of the tropopause at 0.1 bar and using the lapse rate determine the temperature profile down to the surface.

The surface temperature is thus solely a function of gravity, atmospheric mass, atmospheric heat capacity and has no relationship to radiative forcing from greenhouse gases.

The mean emission height on any planet will thus be the height at which T determined from the lapse rate is equal to the equilibrium T with the Sun [for conservation of energy].

DeleteJoseph E Postma says:

ReplyDelete2013/12/09 at 7:04 PM

Yes that is really really neat about the 0.1 bar thing. Why? Because one thing I’ve always found curious is that, given all the differences in insolation at the surface (Venus has hardly any direct insolation at its ground surface) and other atmospheric differences, if you combine the radiative surface with the atmosphere’s lapse rate, you always calculate the near-surface-air temperature correctly. So if IR opacity is largely dependent simply on pressure, then bang, that defines where the radiative surface is going to be and then it automatically follows what the air temperature at the surface will be given the particular lapse rate. Great stuff.

Here's the whole paper"

ReplyDeletehttp://faculty.washington.edu/dcatling/Robinson2014_0.1bar_Tropopause.pdf

http://www.lpi.usra.edu/planetary_atmospheres/presentations/Catling.pdf

Deletehttp://arxiv.org/ftp/arxiv/papers/1209/1209.1833.pdf

ReplyDeletePaper written in 1930 corroborates the effect of gravity upon adiabatic gases to establish a temperature profile:

ReplyDeletehttp://authors.library.caltech.edu/2574/1/TOLpr30a.pdf

Richard Tolman wrote a paper, “On the weight of heat, and thermal equilibrium in general relativity”. In it, he derives first a classical approximation and then the relativistic solution to the differences of temperature with distance from the center of a self gravitating gas in thermal equilibrium. In the conclusion he writes:

“Qualitatively, the increase in equilibrium temperature which was found to accompany decrease in gravitational potential, may be regarded as due to the necessity of having a temperature gradient to prevent the flow of heat from places of higher to those of lower potential energy; and quantitatively, a first approximation to the magnitude of this temperature gradient was obtained by modifying the classical thermodynamics merely by ascribing to each given intrinsic quantity of energy the right additional quantity of potential gravitational energy.”

He then goes on to note the necessity of a more accurate formulation to account for relativistic effects.

He goes on, in his final paragraph to write:

“This discovery of a dependence of equilibrium temperature on gravitational potential must be regarded as something essentially new in thermodynamics, since uniform temperature throughout any system that has come to equilibrium has hitherto been taken as an inescapable part of any thermodynamic theory. The new result hence has a very considerable theoretical interest, and even though the effect of gravitational potential on temperature may usually be extremely small the result may sometime be of experimental and observational interest.”

Dr Curry: "The linear [IPCC] model, with climate change radiatively forced...unlikely to improve climate understanding" feedly.com/k/1lsVaYr

ReplyDeletePlease see this new post for many additional papers which support the fact that the entire 33K "greenhouse effect" is solely due to gravity, atmospheric mass, solar insolation, and is independent of "radiative forcing from greenhouse gases."

ReplyDeletehttp://hockeyschtick.blogspot.com/2014/03/why-ideal-gas-law-gravity-atmospheric.html

In the light of the above you may find this helpful:

ReplyDeletehttp://www.newclimatemodel.com/the-gas-constant-as-the-global-thermostat/

Stephen Wilde

For a lot more detail see here:

ReplyDeletehttp://www.newclimatemodel.com/the-ignoring-of-adiabatic-processes-big-mistake/

from December 2012

Stephen Wilde

http://tallbloke.wordpress.com/2012/01/16/the-gravity-of-some-matter/#comment-14236

ReplyDeletehttp://tallbloke.wordpress.com/2012/01/04/the-loschmidt-gravito-thermal-effect-old-controversy-new-relevance/#comment-12990

Just started looking at this site- in notes part 4, 6.5K/km (lapse rate) x 5km = 33K . Why 5 km? What is the significance of 5 km? Thanks!

ReplyDeleteHeight of the troposphere is ~5-6 km

DeleteThe lapse rate only applies to the troposphere, therefore multiply height of troposphere * average lapse rate = 33K greenhouse effect

The Robinson & Catling model puts CO2 in its place. It is not the "Magic Gas" responsible for the "Greenhouse Effect" (Arrhenius,1896).

ReplyDeletehttp://diggingintheclay.wordpress.com/2014/04/27/robinson-and-catling-model-closely-matches-data-for-titans-atmosphere/

While I agree with MS on most things the 255 K "Equilibrium Temperature" for Earth is incorrect. It is based on good mathematics spoiled by incorrect assumptions about our planet's surface.

A more realistic value would be 201 Kelvin. That would be 197 K (the average temperature of our Moon) plus 4 K to allow for a 27 faster rate of rotation.

http://tallbloke.wordpress.com/2014/04/18/a-new-lunar-thermal-model-based-on-finite-element-analysis-of-regolith-physical-properties/

Thanks, I also corresponded with Dr. Robinson and he confirmed that the "GHE" is primarily a function of atmospheric mass/gravity and the 0.04% CO2 adds very little mass therefore very little effect on the GHE.

Deleteconvection ends in the tropopause

ReplyDeletehttp://onlinelibrary.wiley.com/doi/10.1029/2001JD001048/abstract

http://tallbloke.wordpress.com/2014/03/23/challenging-arrhenius-again/

ReplyDeletehttp://tallbloke.wordpress.com/2014/03/11/effective-emission-height/

ReplyDeletestratospheric cooling

ReplyDeletehttp://www.nature.com/nclimate/journal/v3/n10/full/nclimate1908.html

emission spectra

ReplyDeletehttp://www.science-skeptical.de/klimawandel/klimaskeptiker-irrtuemer-welche-argumente-klimaskeptiker-keinesfalls-in-der-klimadebatte-vorbringen-sollten/0011565/

emission spectra

ReplyDeletehttp://agwobserver.wordpress.com/2010/03/10/simple-observational-proof-of-greenhouse-effect/

ideal gas calculator

http://www.ajdesigner.com/idealgas/ideal_gas_law_temperature_equation.php

tropopause data:

http://onlinelibrary.wiley.com/doi/10.1029/2006JD007363/abstract

stratosphere, mesospere trends

http://onlinelibrary.wiley.com/doi/10.1029/2001GL013633/abstract

http://www.csc.kth.se/~cgjoh/climatethermoslayer.pdf

ReplyDeleteThe adiabatic lapse rate does not describe the temperature profile of the atmosphere. It describes the temperature change of a parcel of air that is lifted adiabatically.

ReplyDeleteThe temperature profile of the atmosphere is driven by the distance relationship between the main heating source (the Earth) and your altitude. Further away is colder.

If you want another calculation that demonstrates this (and is not referring erroneously to something else) you can use the hydrostatic equation to derive the temperature-dependent pressure profile of the atmosphere, and sub in a near-zero temperature lapse rate. The pressure profile doesn't change remarkably: it converges to a particular exponential decay. As in, the pressure profile can remain about the same as it is right now, even with increasing temperature with altitude.

The lapse rate absolutely does describe the temperature profile of the atmosphere, dT/dh = -g/Cp

DeleteThe temperature profile of the troposphere is approx:

255K [Equilibrium temp with Sun] + Adiabatic Lapse Rate.

Start at the middle of mass of the atmosphere ~5.2km where T=255K=Equilibrium temp with Sun=Average emission height

255 + 5.2km*6.5K/km [average lapse rate] = 288K = surface temperature of Earth

As shown in this diagram, which also shows temperature profile and pressure as essentially parallel lines within the troposphere up to the radiative/convective boundary/tropopause where P=100 bars.

(This is Alexander Coulter, I'm on a different computer sorry.)

ReplyDelete"The lapse rate absolutely does describe the temperature profile of the atmosphere, dT/dh = -g/Cp"

Just because you use an equation that has a change in temperature over a change in height does not mean that it actually describes the change in temperature of the static atmosphere. It's called the "adiabatic" lapse rate for a reason: it describes a lapse rate during an adiabatic process, i.e. adiabatic lifting. So, it describes the temperature change of a moving air parcel not exchanging heat with its environment.

There is the adiabatic lapse rate, which is derived from the Poisson relations in an adiabatic transformation. It describes the change in temperature of a parcel of air that undergoes an adiabatic lift (or descent). Then there is the environmental lapse rate, which describes the temperature profile of the atmosphere.

You should consider two things. The first, consider a 1D atmosphere profile, with the material for an atmosphere "frozen" on the surface of a planet without insolation. This atmosphere will be transparent to IR: it cannot radiate energy away. No greenhouse gases. Now add sunlight at ~390 W/m^2 (a greater value than current insolation, keep in mind). The surface will sublime and warm due to conduction, and warmer less buoyant air will rise adiabatically.

Since heat loss from radiation is the only way energy can leave the planetary system, the surface of the planet (and the surface air as well because of conduction) will warm until it reaches 288K. This is the blackbody temperature of a body emitting at 390 W/m^2. If gravity is the same as on our planet, and the atmosphere has the same heat capacity, then convection will continue until the environmental lapse rate equals the dry adiabatic lapse rate of -9.8K/km. It will approach this value from an initially *high* rate of temperature change in the atmosphere (say, -30K/km) because we started with a very thin atmosphere that's expanding and rising as it warms. The environmental lapse rate cannot get lower by convection, as anything less (say, -5K/km) would be a stable condition where rising air would just sink back to its initial level.

When convection stops we have conduction take over. Conduction will always carry heat from high to low: even though you will not get bulk movement of air parcels as through convection, you will end up with warmer air close to the surface transporting heat via conduction to higher layers until an isothermal atmosphere is reached. This is an atmosphere without a temperature gradient, that still has an adiabatic lapse rate, that is still stable.

It is only by adding absorptivity (adding greenhouse gases) that conduction will NOT carry an atmosphere through to isothermal, because an isothermal but radiatively absorptive atmosphere will lose energy via radiation; and it will lose it to space. So if we take our example atmosphere, and all of a sudden make it absorptive (and thus emissive), the top layers will cool until you reach a height where photons cannot escape any more because of collisions taking away energy absorbed more rapidly than it can be emitted. But you cannot have a top layer that is cold, immediately transform into a warm lower layer: convection will recreate the environmental lapse rate, and the atmosphere will be isothermal above the afore-stated height (at which it can radiate away), and will have some ELR that will approach the ALR depending on how strong of an absorber it is.

(pt 2)

ReplyDeleteSecond thing you should consider is the derivation of the temperature-dependent pressure profile for an atmosphere. I'll derive it (in this equation, g is negative, as I like to use "up" as a positive direction):

dp/dz = (rho)*g

dp = rho * g * dz

dp = (p / R / T) * g * dz

dp/p = g/R * 1/T * (dT/dT) * dz

dp/p = g/R * (dz/dT) * dT/T

dp/p = g/R * 1/tau * dT/T

ln(p_z / p_0) = (g / R / tau) * ln(T_z / T_0)

p_z / p_0 = (T_z / T_0)^(g / R / tau)

p_z = p_0 * (T_z / T_0)^(g/R/tau)

p_z = p_0 * ( (T_0 + z*tau) / T_0)^(g/R/tau)

Here "tau" is the environmental temperature lapse rate. Plug this equation into Excel, and give tau a value that is very very close to zero. And, give it a value that matches the adiabatic lapse rate (~0.0098 K/m). Graph the pressure profiles against each other, and when you do, please explain to me how a nearly isothermal atmosphere could possible correspond to an exponentially decreasing pressure profile.

(Hint: the equation is of the form (1 + 1/n)^n, which in the limit is 1/e.)

(Still Alex Coulter)

ReplyDeleteTo actually modify my first part of the previous set of comments: if the atmosphere becomes radiatively absorptive (and emissive), it will begin to absorb radiation and translate that into kinetic motion below the height that will become the new tropopause; this results in warming below the tropopause. More absorbed energy at lower altitudes (higher volumetric concentration of the gases due to higher pressure) means it is warmer below than it is above. That is what helps create the ELR, not necessarily cooling of the upper layers. At radiative equilibrium, the layers above the troposphere should be losing radiation at each wavelength at the same rate they are gaining radiation at that wavelength. It's my understanding that above the tropopause it would be isothermal, and also at the blackbody temperature.

Maxwell and many others have shown that an atmosphere without GHGs would not be isothermal as you falsely claim.

ReplyDeletehttp://hockeyschtick.blogspot.com/2014/05/maxwell-established-that-gravity.html

http://hockeyschtick.blogspot.com/2014/03/why-ideal-gas-law-gravity-atmospheric.html

Do you not know what causes convection? In order to have mass movement of energy in a parcel of air, that parcel of air needs to obtain that energy. How will that parcel obtain its energy?

ReplyDelete• Conduction? I've already established (and Maxwell agrees) that with only conduction, you get an isothermal atmosphere.

• Radiation? No, because we're working without greenhouse gases.

• Convection? That is begging the question.

In a simple atmosphere, convection stops without thermal absorptivity. You can quote Maxwell all you want, but you don't seem to understand what he is saying.

You still haven't responded to the second part of my comment, too, regarding the pressure lapse rate equation.

Solar radiation heats the surface -> heated air packet rises, expands, and cools via convection until releasing latent heat in the upper atmosphere -> air packet then descends, compresses, and heats due to gravity. This process continues ad infinitum, no greenhouse gases required. The Sun and gravity drive this process, not GHGs, and it would occur in an atmosphere comprised of 100% N2 & O2, as well as in our atmosphere with >99% N2 & O2. Maxwell makes no mention of "radiative forcing" and indeed the erroneous concept of "radiative forcing" of the atmosphere hadn't even been invented by the erroneous Arrhenius at the time Maxwell wrote his theory of heat.

DeleteYou're describing a very wide array of things, one of which actually counters your very point.

DeleteFor starters, I had just described an atmosphere where convection was driven by conduction between air and ground. In that atmosphere, the convection *stopped* once the environmental lapse rate reached the adiabatic lapse rate, and further conduction within the air itself drove the atmosphere to isothermal. This is exactly what Maxwell described. *Please* describe how convection operates if NOT for thermal absorptivity. Because purely conduction will lead to an isothermal atmosphere.

Second, *non-condensible gases do not release latent heat*. If the atmosphere was entirely made out of nitrogen and oxygen, there would be *no latent heat* because those gases do not condense to form liquid in the atmosphere.

And are you going to respond to the math that I gave you or are you not?

"...further conduction within the air itself drove the atmosphere to isothermal. This is exactly what Maxwell described."

DeleteFalse. Maxwell first described what you are saying:

"”The second result of our theory relates to the thermal equilibrium of a vertical column. We find that if a vertical column of a gas were left to itself, till by the conduction of heat it had attained a condition of thermal equilibrium, the temperature would be the same throughout [i.e. isothermal"], or, in other words, gravity produces no effect in making the bottom of the column hotter or colder than the top. This result is important in the theory of thermodynamics, for it proves that gravity has no influence in altering the conditions of thermal equilibrium in any substance, whether gaseous or not...."

But then described why this does NOT apply to the atmosphere:

”This result is by no means applicable to the case of our atmosphere. Setting aside the enormous direct effect of the sun’s radiation in disturbing thermal equilibrium, the effect of winds in carrying large masses of air from one height to another tends to produce a distribution of temperature of a quite different kind, the temperature at any height being such that a mass of air, brought from one height to another without gaining or losing heat, would always find itself at the temperature of the surrounding air. In this condition of what Sir William Thomson has called the convective equilibrium of heat, it is not the temperature which is constant, but the quantity Ï [entropy], which determines the adiabatic curves.

In the convective equilibrium of temperature, the absolute temperature is proportional to the pressure raised to the power (Îł-1)/Îł, or 0,29.

The extreme slowness of the conduction of heat in air, compared with the rapidity with which large masses of air are carried from one height to another by the winds, causes the temperature of the different strata of the atmosphere to depend far more on this condition of convective equilibrium than on true thermal equilibrium.”

No radiative forcing or greenhouse gases requirement whatsoever to maintain a temperature gradient, only gravity/atmospheric mass/convection/heat capacity.

Your assumption that the atmosphere would be isothermal in the absence of GHGs is false, thus so are your conclusions regarding the lapse rate.

Non-condensible gases do not release latent heat, but a dry air parcel still cools as it rises and expands and gains potential energy [from gravity], establishing the dry adiabatic lapse rate.

I've supplied many links explaining why a non-GHG atmosphere would not be isothermal, you have not said anything convincing otherwise, thus we are at an impasse. Bye

recommended:

ReplyDeletehttp://chiefio.wordpress.com/2014/06/01/le-chatelier-and-his-principle-vs-the-trouble-with-trenberth/

New paper says climate models haven't previously considered radiative-convective equilibrium over land

ReplyDeletehttp://journals.ametsoc.org/doi/abs/10.1175/JCLI-D-13-00654.1?af=R

Kristian says:

ReplyDeleteJune 16, 2014 at 10:55 am {comment from WUWT}

First of all. Increased evaporation is a NEGATIVE feedback to surface heating, not a positive feedback to atmospheric heating. Latent heat through evaporation transferred from surface to atmosphere is a (the main) CAUSE of atmospheric heating:

http://i1172.photobucket.com/albums/r565/Keyell/HeatamprainJRA-25_zpsda38e24a.png

Secondly, one needs to move away from the completely outdated (19th Century) ‘confined space heating’ idea of CO2 warming. Even ‘climate science’ realised it doesn’t work in the real world already many decades ago. The basic (and necessary) premise behind this idea is that as the IR absorption ability of the lower tropospheric air mass grows stronger with an increase in CO2, there is no buoyant response, no convective change. We all know from everyday experience that this simply can’t and does not happen in the open atmosphere. Energy doesn’t accumulate down low. It is brought up. Automatically. It can happen in a closed glass box in a lab experiment. But that’s not the real earth system. The analogy fails. You can’t reduce the natural temperature gradient away from the solar-heated surface of the earth by simply letting the lower troposphere absorb more surface radiation. In this case, buoyancy wouldn’t simply constitute a partially offsetting negative feedback to CO2 warming. It would completely nullify it, pretty much instantly.

‘Climate science’ has of course come up with a more ‘clever’ explanation of how more CO2 in the atmosphere is allegedly supposed to make the surface warmer: The (in)famous ‘raising of the effective radiating level (ERL)’ hypothesis. Which strangely hinges on heating starting from a radiative imbalance aloft and propagating down the lapse rate ladder to end up on the surface. Utterly speculative, counter-logical, un-physical and totally unsupported by real-world evidence, of course. But still what all the warmists fall back on when they realise they can no longer push the ‘heating by back radiation’ nonsense on normal thinking people.

http://tallbloke.wordpress.com/2014/07/13/the-so-called-effective-height-of-emission-vs-the-actual-height-of-emission-which-is-more-informative/comment-page-1/#comment-83365

ReplyDelete